5y^2+4y+1=29

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Solution for 5y^2+4y+1=29 equation:


Simplifying
5y2 + 4y + 1 = 29

Reorder the terms:
1 + 4y + 5y2 = 29

Solving
1 + 4y + 5y2 = 29

Solving for variable 'y'.

Reorder the terms:
1 + -29 + 4y + 5y2 = 29 + -29

Combine like terms: 1 + -29 = -28
-28 + 4y + 5y2 = 29 + -29

Combine like terms: 29 + -29 = 0
-28 + 4y + 5y2 = 0

Factor a trinomial.
(-14 + -5y)(2 + -1y) = 0

Subproblem 1

Set the factor '(-14 + -5y)' equal to zero and attempt to solve: Simplifying -14 + -5y = 0 Solving -14 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '14' to each side of the equation. -14 + 14 + -5y = 0 + 14 Combine like terms: -14 + 14 = 0 0 + -5y = 0 + 14 -5y = 0 + 14 Combine like terms: 0 + 14 = 14 -5y = 14 Divide each side by '-5'. y = -2.8 Simplifying y = -2.8

Subproblem 2

Set the factor '(2 + -1y)' equal to zero and attempt to solve: Simplifying 2 + -1y = 0 Solving 2 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1y = 0 + -2 -1y = 0 + -2 Combine like terms: 0 + -2 = -2 -1y = -2 Divide each side by '-1'. y = 2 Simplifying y = 2

Solution

y = {-2.8, 2}

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